Using the graphing function on your calculator, what is the solution to the system of equations show below?
Y+ 2x = 5
4y+ 5x=14
A. x=2 y=1
B. x= 1, y = 2
O C. More than 1 solution
O D. No solution

x = 2 y = 1

Step-by-step explanation:

Given the system of equation

Y+ 2x = 5 ...1

4y+ 5x=14 2

From 1;

y =5 - 2x 3

Substitute 3 into 2

4(5-2x) + 5x = 14

20 - 8x + 5x = 14

20 - 3x = 14

-3x = 14-20

-3x = -6

x = 6/3

x = 2

Since y = 5-2x

y = 5-2(2)

y = 5-4

y = 1

Hence the required solution is (2,1)

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

idk

step-by-step explanation: