What is the vertex of the graph of the quadratic function f(x) = x2 + 6x +10? F (3,-1)

G(-3,-1)

H(-3,1)

J(3,1)

(-3, 1)    (Answer H)

Step-by-step explanation:

f(x) = x^2 + 6x +10 can be rewritten by "completing the square" as

f(x) = (x + 3)^2 + 1, and by comparing this to y = (x - h)^2 + k, we see that h is -3, k is 1, so the vertex, (h, k), is at (-3, 1)    (Answer H)

the answer is a

step-by-step explanation:

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carrying installment price - cash price

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