Three airlines serve a small town in Ohio. Airline A has 48% of all scheduled flights, airline B has 35% and airline C has the remaining 17%. Their on-time rates are 81%, 70%, and 41%, respectively. A flight just left on-time. What is the probability that it was a flight of airline A

If a flight just left on-time, the probability that it was a flight of airline A is 56.06%.

Step-by-step explanation:

Since three airlines serve a small town in Ohio, and Airline A has 48% of all scheduled flights, airline B has 35% and airline C has the remaining 17%, and their on-time rates are 81%, 70%, and 41%, respectively, if a flight just left on-time, to determine what is the probability that it was a flight of airline A the following calculation must be performed:

A = 0.48 x 0.81 = 38.88

B = 0.35 x 0.7 = 23.5

C = 0.17 x 0.41 = 6.97

38.88 + 23.5 + 6.97 = 100

38.88 = X

69.35 = 100

38.88 = X

38.88 x 100 / 69.35 = X

3,888 / 69.35 = X

56.06 = X

Therefore, if a flight just left on-time, the probability that it was a flight of airline A is 56.06%.

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

~