Factor the quadratic expression in the equation y = 2x2 + 8x - 154 and find the zeros of the equation. Then use the zeros to find the line of symmetry of the parabola represented by the equation.

What is the equation for the line of symmetry of the parabola represented by the equation
y = 262 + 8x - 154?

Enter your answer as the correct equation like this: x = 42

zeros: -11 , 7

Line of symmetry: x = -2

Step-by-step explanation:

y = 2x² + 8x - 154 = 2*(x² + 4x - 77) = 2*(x+11)(x-7)

y = 0

x = - 11 or x = 7

line of symmetry: x = 1/2 (-11 + 7) = -2

2x² + 8x - 154 = 2*(x² + 4x +4) - 162 = 2 * (x+2)² - 162

vertex (h , k): h = -2 , k = -162

Line of symmetry: x = -2

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length