A coin is tossed twice. Let Z denote the number of heads on the first toss and W the number of heads on the second toss. If the coin is unbalanced and a head has a 40% chance of occurring, find

0.64

Step-by-step explanation:

Prob ( Head ) = 40% = 0.4 , Prob ( Tail )  = 1 - 40% = 60% = 0.6

4 outcomes =  (Head Tail) , (Tail Head) , (Head Head) , (Tail , Tail)

Prob (Atleast one head) = Pr (Head Tail) + Pr (Tail Head)  + Pr (Head Head)

(0.4) (0.6) +  (0.6) (0.4) = 0.24 + 0.24 + 0.16 = 0.64

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step-by-step explanation: