I will give brainlest please help

The center of the circle would be (5,-8)

This is because you inverse the sign within the equation for the x/y coordinate part of it. Therefore, for this question:

(x-5)^2+(y+8)^2 = 121

The center would be (5,-8), since there is (x-5) and (y+8).

The radius of the circle would be 11

This is because within the equation for the circle, the finishing number is the radius squared. This means that if you square root this finishing number, you would get the radius. So with this question:

(x-5)^2+(y+8)^2 = 121

By doing √121, you would get 11 as the radius.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

mk./km: lm

step-by-step explanation:

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; mk

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