How is y=2x^2-8x+9 rewritten in vertex form.

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  y = 2(x -2)^2 +1

Step-by-step explanation:

Start by factoring the leading coefficient from the x-terms.

  y = 2(x^2 -4x) +9

Now identify the coefficient of x, -4, and figure half of that: -2. Square this number and add it inside the parentheses. At the same time, subtract the equivalent value outside parentheses. (The leading coefficient must be taken into account.)

  y = 2(x^2 -4x +4) +9 -2(4)

Put in the desired form.

  y = 2(x -2)^2 +1

This matches vertex form ...

  y = a(x -h)^2 +k . . . . . . . . . vertical scale factor 'a'; vertex (h, k)

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy