144 coins are divided equally among some children. If there were 3 fewer children,
each child would have 16 coins. How many
children are there?​

Consider the number of children to be x.

So, 144 coins were divided amongst x children.

For x-3 children, each child would have 16 coins

So, (x-3)*16=144

Solving for x, x-3=144/16

or x-3=9

or x=9+3=12

Answer is 12

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.

there is nothing below so i cannot

step-by-step explanation: