Write an equation of a line that passes through the point (4, 3) and is perpendicular to the graph of the equation y=-1/3 +4.​

y=3x-9

Step-by-step explanation:

Hi there!

we are given a point (4,3), and a line (y=-1/3x+4)

Perpendicular lines have slopes that are negative and reciprocal; if they are multiplied together, the result is -1

first, let's find the slope of the new line.

we can find it with this formula: (m=slope)

-1/3m=-1

multiply both sides by -3

m=3

here's our equation so far, written in y=mx+b form, where m is the slope and b is the y intercept

y=3x+b

we need to find b

Because the line passes through the point (4,3), we can use it to find b

substitute x as 4 and y as 3

3=3(4)+b

multiply

3=12+b

-9=b

substitute into the equation

y=3x-9

Hope this helps!

answer: huh

step-by-step explanation:

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50