A motorcyclist is riding towards a building that has its top 300 meters higher than her viewing position on the road below. When she is 400 meters away from the building, the motorcyclist notes that the angle of elevation from her position to the top of the building is increasing at the rate of 0.03 radians per second. Find the speed of the motorcycle at the time when x = 400 meters and dθ
dt = 0.03 radians per second.

i got 142 as my answer

step-by-step explanation:

step-by-step explanation:

where is the diagram? shown below where? ?

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)