Write a equation that represents the line. Use exact numbers

HELP PLEASE I WILL GIVE 20 POINTS

y= 4/5x -18/5

Step-by-step explanation:

First step is to find the slope using the points

(-3,-6) and (2,-2)

m = (y2-y1)/(x2-x1)

    = ( -2- -6)/(2 - -3)

    = (-2+6)/(2+3)

    = 4/5

The using the slope intercept form of a line

y = mx+b where m is the slope and b is the y intercept

y = 4/5 x + b

Substitute a point into the equation

-2 = 4/5(2)+b

-2 = 8/5 +b

Subtract 8/5 from each side

-2 -8/5 =b

-10/5 -8/5 =b

-18/5 = n

y= 4/5x -18/5

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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step-by-step explanation:

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