A small town has two local high schools. High School A currently has 750 students and is projected to grow by 45 students each year. High School B currently has 850 students and is projected to grow by 25 students each year. Let A represent the number of students in High School A int years, and let B represent the number of students in High School B after t years. Write an equation for each situation, in terms of t, and determine after how many years, t, the number of students in both high schools would be the same.​

A=750 +75*t

B=900 +25*t

There would be 975 students in each high school in year 3 when they are expected to have the same number of students.

Step-by-step explanation:

A = B

750 +75*t=900 + 25*t

Solving:

75*t -25*t= 900 - 750

50*t= 150

t=3

This indicates that in year 3 both High Schools are projected to have the same number of students. To get that amount, you simply replace this value in the expressions:

A=750 +75*t= 750 +75*3= 975

B=900 + 25*t=900 + 25*3= 975

There would be 975 students in each high school in year 3 when they are expected to have the same number of students.

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

answer: 12

step-by-step explanation:

because yes