A ball is launched from a platform. The equation for the ball's height h at time t seconds after launch is h(t)= -16t^2+153.6t +393.12, where h is in feet. What is the initial height of the ball before launch?

The initial height of the ball before launch is 393.12 feet.

Step-by-step explanation:

The ball's height (), in feet, as a function of time (), in seconds, is represented by . The initial height of the ball before launch is the height of the ball evaluated at :

The initial height of the ball before launch is 393.12 feet.

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step-by-step explanation:

i think the answer is b