Every given minute an ameba is equally likely to do one of 3 things: (1) Die (2) Divide into two (3) Stay the same. If the ameba divides, each of the two cells will continue the above cycle independently. What is the probability that the ameba colony generated from a single cell will eventually die out. Required:
What is the probability that the ameba colony generated from a single cell will eventually die out?

1

Step-by-step explanation:

we have the probability of dyng = 1.3

we have probability of ying =

p0 = p1 = p2 = p3 = 1/3

d = dying

we cross multiply from here

3d = 1+d+d2

3d-d = 1+d2

2d = 1 + d2

(d-1)2 = 0

2d - 2 = 0

2d = 2

divide through by 2

d = 1

therefore there is a a confirmed probability that the ameba from a single cell is eventually going to die out.

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9