Andrea has 4 hours to spend training for an upcoming race. She completes her training by running full speed the distance of the race and walking back the same distance to cool down. If she runs at a speed of 8mph and walks back at a speed of 2mph, how long should she plan to spend walking back?

Time spend in walking = 3.2 hour = 3¹/₅ hour

Step-by-step explanation:

Given:

Total time taken = 4 hour

Speed when run = 8 mph

Speed when walk = 2 mph

Find:

Time spend in walking

Computtaion:

We know that;

Time = Distance / Speed

Assume;

One side distance = D

So,

D/8 + D/2 = 4

2D + 8D = 64

10D = 64

D = 6.4

So,

One side distance = 6.4 mile

Time spend in walking = One side distance / Speed when walk

Time spend in walking = 6.4 / 2

Time spend in walking = 3.2 hour = 3¹/₅ hour

answer: no

step-by-step explanation:

you are only given the cost not the amount of pounds.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.