A fair coin is tossed three times. What is the probability of getting at least two heads?

The answer is 50%

if you list out the possibilities, you get

(H being heads, T being tails)

HHH <- 3 heads
HHT <- 2 heads
HTH <- 2 heads
HTT
THH <- 2 heads
THT
TTH
TTT

we counted 4 of them to have at least 2 heads out of the 8 possibilities

4/8 = 1/2 which is 50%

You need to use the logical equivalence lawsin this problem you have to use definition of implication(~p v q)i hope this