Find two consecutive odd integers such that the square of the first added to 3 times the second, is 24. Part a: Define the variables. Part b: Set up an equations that can be solved to find the integers. Part c: Find the integers.

Given:

There are two consecutive odd integers such that the square of the first added to 3 times the second, is 24.

To find:

Part a: Define the variables.

Part b: Set up an equations that can be solved to find the integers.

Part c: Find the integers.

Solution:

Part a:

Let x be the first odd integers. Then next consecutive odd integer is , because the difference between two consecutive odd integers is 2.

Part b:

Square of first odd integers =

Three times of second odd integers =

It is given that the sum of square of first odd integers and three times of second odd integers is 24. So, the required equation is:

Part c:

The equation is:

It can be written as:

Splitting the middle term, we get

-6 is not an odd integer, so and the first odd integer is 3.

Second odd integer =

                                  =

                                  =

Therefore, the two consecutive odd integers are 3 and 5.

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

step-by-step explanation:

1. the cylinder is a. 54

2.   a.108 /