At a bus station, buses begin their routes at 6.Am. The schedule for two of the buses is based on time intervals listen below

They will both leave at 07:15am

Step-by-step explanation:

Given

Required

Next time both buses leave the station at the same time

To do this, we list out the multiples of 75 and 15.

We have:

After the first departure at 06:00 am (0 minutes) for both buses respectively, the next time they both leave is after 75 minutes (common multiple)

So, the time is:

x= -3

step-by-step explanation:

step 1: simplify brackets

4 - x - 1 = 6

step 2: simpilfy

3 - x = 6

step 3: subtract 3 from both sides

-x = 6 - 3

step 4: simpilfy 6 - 3

-x = 3

step 5: multiply both sides by -1

x = -3

36

step-by-step explanation: