There are 10 2/15 kg of watermelons and coconuts on a truck. The weight of the watermelons is 3 3/5 times that of the coconuts. How heavy are the coconuts on the truck, in kg?

2 7/76 kg

Step-by-step explanation:

Let the weight of

Watermelons = x

Coconut = y

There are 10 2/15 kg of watermelons and coconuts on a truck.

x + y = 10 2/15

x = 10 2/15 - y

x = 152/15 - y Equation 1

The weight of the watermelons is 3 3/5 times that of the coconuts.

x = 3 3/5 × y

x = 18/5 × y

x = 18y/5

How heavy are the coconuts on the truck, in kg?

Find y

We substitute 18y/5 for x in Equation 1

x = 152/15 - y

18y/5 = 152/15 - y

18y /5 + y = 152/15

Multiply through by 15

18y/5 × 15 + y × 15 = 152/15 × 15

3 × 18y + 15y = 152

54y + 15y = 152

69y = 152

y = 152/69

y = 2 14/152

y = 2 7/76 kg

Therefore, the weight of the coconuts are 2 7/76 kg

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.

answer: - (a)

(b) 88 seats

step-by-step explanation:

given: in an auditorium, there are 22 seats in the first row and 28 seats in the second row.

thus first term=

second term=

the number of seats in a row continues to increase by 6 with each additional row.

⇒d= 6

a) given formula :

b)   let the number of seats (n) = 12

substitute n=12 in the explicit rule formed in (a)

∴there are 88 seats in 12 rows.