(Find the expected value of the winnings from a game that has the following payout probability) I have all the answers with work shown and how to solve on the second image
Hope this help you guys :)

The expected value is $2.1

Step-by-step explanation:

If we have an event with some given outcomes:

x₁, x₂, ..., xₙ

Such that each one of these outcomes has the correspondent probability:

p₁, p₂, ..., pₙ

The expected value is:

EV = p₁*x₁ + ... + pₙ*xₙ

In this case we have a table with the events (the payouts) and the probability for each one, so we have:

x₁ = $0

p₁ = 0.5

x₂ = $2

p₂ = 0.2

x₃ = $4

p₃ = 0.15

x₄ = $6

p₄ = 0.1

x₅ = $10

p₅ = 0.05

Now we can just replace these in the expected value equation, so we get:

EV = $0*0.5 + $2*0.2 + $4*0.15 + $6*0.1 + $10*0.05 = $2.1

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3