Find the Z-scores that separate the middle 22% of the distribution from the area in the tails of the standard normal distribution. The Z scores are ?
Find the value of z a The value of α = 0.27
The value of z 0.27 is
Find the Z-score such that the area under the standard normal curve to the left is 0.33
is the z - score such that the area under the curve to the left is 0.33.

0.279

0.613

-0.44

Step-by-step explanation:

The Zscore that seperates the middle 22% of the distribution ; could be obtained thus. The midpoint is the mean and the probability to either the right or left could be obtained.

To obtain the Zscore that seperates the middle 22% is equivalent to :

The probability to the left of the distribution :

P(x < (0.5 + 0.22/2) = p(x < 0.61)

Using the Z probability calculator :

P(x < 0.61) is equivalent to a Zscore of 0.279

α = 0.27

Z(1 - α) = Z(1 - 0.27) = Z0.73 = p(Z < 0.73) = 0.613

P(x < 0.33) = - 0.44 (Z probability calculator)

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: