Find the number of x-interpects of y=-x^2+4x-12

x = -2 + 2√2 i and -2 - 2√2 i

Step-by-step explanation:

Given the function, y=-x^2+4x-12

x intercept occurs at y =  0

Substitute y = 0

0=-x^2+4x-12

x^2 - 4x + 12 = 0

Factorize

x = -4±√4²-4(12)/2

x = -4±√16-48/2

x = -4±√-32/2

x = -4 ± √32 i/2

x = -4+4√2 i/2 and x =-4-4√2 i/2

x = -2 + 2√2 i and -2 - 2√2 i

don't know sorry bru

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v