Suppose the height of a ball in feet is given by the quadratic equation below, where T is in seconds. What expression will give the time when the ball reaches its maximum height? h=-16t^2+50t+8. Please look at the image for the available answers. Thank you.

t = -50/(2 * (-16))

Step-by-step explanation:

For quadratics of the form

y = ax^2 + bx + c

the x coordinate of the vertex is

x = -b / 2a

----------------------

h = -16t^2 +50t + 8

a = -16

b = 50

t at Vertex

t = -50/(2 * (-16))

d) 48

step-by-step explanation:

16,32,48,64,80,96,112,128,144,160,176,192,208,224,240,256,272,288,304,320,336