A signalized intersection has a cycle length of 70 seconds. For one traffic movement, the displayed all-red time is set to 2 seconds while the displayed yellow time is 5 seconds. The effective red time is 37 seconds and the total lost time per cycle for the movement is 4 seconds. What is the displayed green time for the traffic movement

the displayed green time for the traffic movement is 30 seconds

Step-by-step explanation:

Given the data in the question;

Cycle length; C = 70 seconds

Displayed all-red time; AR = 2 seconds

Displayed yellow time; Y = 5 seconds

Effective red time; r = 37 seconds

total lost time per cycle; = 4 seconds

the displayed green time for the traffic movement; G = ?

First we determine the Effective green time ( g );

Effective red time; r = Cycle length; C - Effective green time ( g )

so,

Effective green time ( g ) = C - r

we substitute

Effective green time ( g ) = 70 seconds - 37 seconds

Effective green time ( g ) = 33 seconds

Now,

Effective green time ( g ) = displayed green time; G + Displayed yellow time; Y + Displayed all-red time; AR - total lost time per cycle;

i.e

g = G + Y + AR -

we substitute

33 = G + 5 + 2 - 4

33 = G + 3

G = 33 - 3

G = 30 seconds

Therefore, the displayed green time for the traffic movement is 30 seconds

yes. we do proportions in probabilities.

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743