find the measure of the angle of elevation of the sun to the nearest degree, if a 100ft tall building casts a 150ft shadow.​

33.7º

Step-by-step explanation:

tan  = opp/adj

tan∅ = 100/150 = 2/3

∅ = arctan 2/3

∅ = 33.690067525979787

33.7º

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

is there a question here?

step-by-step explanation: