Escriba los números racionales que corresponden a los puntos A, B, C, D y E que están representados en la recta numérica.

Point A = -1 4/6 or - 1 2/3

Point B = -5/6

Point C = 1 / 6

Point D = 4/6 or 2/3

Point E = 1 4/6 or 1 2/3

Step-by-step explanation:

To obtain an solution, we need to kno wthe unit each tick mark in between any two labeled point represent on the number line.

For each unit of 1 on the number line, there are 6 tick marks

Hence, distance between each tick mark = 1 / 6

Point A = 2 tick marks to the right of - 2

Point A = - 2 + (2 * 1/6) = - 2 + 2/6 = - 2 + 1/3 = - 1 2/3 or - 1 4/6

Point B is 1 tick mark to the right of - 1

Point B = - 1 + 1/6 = - 5/6

Point C is 1 tick mark to the right of 0

Point C = 0 + 1/6 = 1/6

Point D is 4 tick mark to the right of 0

Point D = 0 + (4 * 1/6) = 4/6 or 2/3

Point E is 4 tick mark to the right of 1

Point D = 1 + (4 * 1/6) = 1 4/6 or 1 2/3

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

im with everythinglos so yeahhhhh

step-by-step explanation: