A card is drawn at random from an ordinary pack of playing cards. What is the probability that it is neither a face card nor a black card? 16/52 = 4/13 10/52 = 5/26 14/52 = 7/26 20/52 = 5/13

20 / 52 = 5 / 13

Probability(P) is the likelihood of occurrence of an event. It is given by;

P = total number of favourable outcomes ÷ total number of possible outcomes

In a pack of playing cards, there are 52 cards altogether.

Therefore, the total number of possible outcomes = 52

To get the probability that a card drawn at random is neither a face nor a black card, the following should be noted.

i. There are 12 face cards in the pack. These are the kings (4 cards), queens(4 cards) and the jacks (4 cards).

Therefore, number of cards that are not face cards = 52 - 12 = 40

ii. Black cards are half of the total number of cards = 26.

These black cards contain half of the kings, queens and jacks cards = 6 which are already included in the face cards. Therefore, the remaining black cards will be 26 - 6 = 20

Neither a face card nor a black card = 40 - 20 = 20 [number of favourable outcomes]

The probability of getting neither a face card nor a black card is

=> total number of favourable outcomes ÷ total number of possible outcomes

=> 20 / 52 = 5 / 13

step-by-step explanation:

their are no angles. sorry cant .

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1