Given: AB and AC are congruent; AD is a perpendicular bisector of BC Prove: ∠B ≅ ∠C

Put the proof in order.
It is given that AB ≅ AC and that D is the midpoint of BC.
If ΔABD ≅ ΔACD, then ∠B ≅ ∠C by CPCTC.
AD is a shared side so AD ≅ AD by the reflexive property.
ΔABD ≅ ΔACD by SSS.
D is the midpoint of BC, so BD ≅ CD.

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step-by-step explanation:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

60°

step-by-step explanation:

the measure angle of c in an isosceles triangle abc is 60° because in isosceles triangle,the measures of all the angles is 60°.

step-by-step explanation:

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