You roll two six-sided number cubes. Let X be the number of odd numbers that show up on the two cubes. What are the possible values of X?
0.1.2
0,1,2,3,4,5,6
1,3,5
0,1,3,5

The possible values of X are 0,1 or 2.

Step-by-step explanation:

In this question:

Two number cubes are going to be rolled.

X is the number of odd numbers that show up on the two cubes.

For each cube, there is one number, which can be even, or odd.

Thus, there can be no odd numbers, one odd number or two odd numbers, and the possible values of X are 0,1 or 2.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

8+10

step-by-step explanation:

you multiply 4 by 2 and 5 by 2