Seeking help to solve the problem shown in the image.

9514 1404 393

  1340

Step-by-step explanation:

The perimeter of a rectangle of length L and width W is ...

  P = 2(L+W)

The perimeter of the rectangle outline of the figure is ...

  P = 2(315 +300) = 2·615 = 1230

That outline is the sum of all of the line segments making up the figure except for two lengths of 55 units each. Adding those, we find the perimeter of the figure to be ...

  P = 1230 +2(55) = 1230 +110 = 1340 . . . units

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Additional comment

It can be convenient to consider the total of horizontal segments and the total of vertical segments. We have shown in the attachment that, except for the 55-unit "indent", the horizontal and vertical lengths are equivalent to those of an ordinary rectangle. Thinking about the problem in this way makes it unnecessary to do the tedious arithmetic necessary to find each segment length. (Here, there is not enough information to do that anyway.)

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length