If f(1)=6f(1)=6 and f(n)=nf(n-1)-4f(n)=nf(n−1)−4 then find the value of f(3)f(3).

49

Step-by-step explanation:

6144

Step-by-step explanation:

If f(1)=6f(1)=6 and f(n)=4f(n-1)f(n)=4f(n−1) then find the value of f(6)f(6).

f(1)=

f(1)=

\,\,6

6

f(\color{darkgreen}{2})=

f(2)=

\,\,4f(\color{darkgreen}{2}-1)

4f(2−1)

=

=

\,\,4f(1)

4f(1)

=

=

\,\,4(6)

4(6)

Substitute f(1)=6

f(2)=

f(2)=

\,\,24

24

f(\color{darkgreen}{3})=

f(3)=

\,\,4f(\color{darkgreen}{3}-1)

4f(3−1)

=

=

\,\,4f(2)

4f(2)

=

=

\,\,4(24)

4(24)

Substitute f(2)=24

f(3)=

f(3)=

\,\,96

96

f(\color{darkgreen}{4})=

f(4)=

\,\,4f(\color{darkgreen}{4}-1)

4f(4−1)

=

=

\,\,4f(3)

4f(3)

=

=

\,\,4(96)

4(96)

Substitute f(3)=96

f(4)=

f(4)=

\,\,384

384

f(\color{darkgreen}{5})=

f(5)=

\,\,4f(\color{darkgreen}{5}-1)

4f(5−1)

=

=

\,\,4f(4)

4f(4)

=

=

\,\,4(384)

4(384)

Substitute f(4)=384

f(5)=

f(5)=

\,\,1536

1536

f(\color{darkgreen}{6})=

f(6)=

\,\,4f(\color{darkgreen}{6}-1)

4f(6−1)

=

=

\,\,4f(5)

4f(5)

=

=

\,\,4(1536)

4(1536)

Substitute f(5)=1536

f(6)=

f(6)=

\,\,6144

6144

\text{Geometric Sequence:}

Geometric Sequence:

Common ratio of 4

6,24,96,384,1536,6144, ...

6,24,96,384,1536,6144,...

\text{Final }

Final

6144

the answer is 0052

0 0 5 2

5 0 2 6 3 5

− 0

2 6

− 0

2 6 3

− 2 5 0

1 3 5

− 1 0 0

3 5