∠A and \angle B∠B are supplementary angles. If m\angle A=(8x-27)^{\circ}∠A=(8x−27) ∘
and m\angle B=(4x+3)^{\circ}∠B=(4x+3)
∘
, then find the measure of \angle A∠A.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

2160ft3

step-by-step explanation:

0.038

step-by-step explanation: