Area of a Triangle Finding the area of a triangle is straightforward if you know the length of the base and the height of the triangle. But is it possible to find the area of a triangle if you know only the coordinates of its vertices? In this task, you’ll find out. Consider ΔABC, whose vertices are A(2, 1), B(3, 3), and C(1, 6); let line segment AC represent the base of the triangle.

Part A
Find the equation of the line passing through B and perpendicular to AC

Part B
Let the point of intersection of A⁢C with the line you found in part A be point D. Find the coordinates of point D.

Part C
Use the distance formula to find the length of the base and the height of ΔABC.

Part D
Find the area of ΔABC.

3.51 (round to the nearest hundreds)

Step-by-step explanation:

PART A

slope of the line passing through AC : (6-1)/(1-2) = 5/-1 = -5

equation of the line passing through B and perpendicular to AC:

y-3 = 1/5(x-3)

y-3 = 1/5x -3/5

y = 1/5 x - 3/5 + 3

y = 1/5 x + (-3+15)/5

y = 1/5 x + 12/5

PART B

line that passes through the points A and C

y-1 = -5(x-2)

y = -5x+10 + 1

y = -5x + 11

Interception of the lines

y = 1/5x + 12/5

y = -5x + 11

-5x + 11 = 1/5x + 12/5

-25x +55 = x + 12

26x = 43

x = 43/26

y = -5(43/26) + 11

y= -215/26 + 11

y = (-215+286)/26 = 71/26

D (1.65, 2.73)

PART C

AC = = 5,09902

BD = = 1,376735

PART D

AREA = (5,09902 * 1.376735)/2 = 3,509999

the answer to the question is a  

it has the same slope and the same y-intercept.

cant

step-by-step explanation: there is no picture