A coin is tossed and a spinner with three equal-sized sections labeled 3, 6, and 9 is spun. What is the probability of getting heads and a number greater than 3? Express as a fraction in simplest form.

The answer is 1/3.

Step-by-step explanation:

A coin has either heads or tails. The odds of a coin getting heads is 1/2.

There are three equal-sized sections with numbers 3, 6 and 9 on the spinner. There are two sections with numbers greater than 3, which are 6 and 9. The odds of getting a number greater than 3 is 2/3.

To find the overall probability of both incidents occurring, the two fractions are multiplied together, which is 1/2 * 2/3 = 1/3

0.333/1/3

Step-by-step explanation:

Well, the probability of getting heads is 1/2 since there are 2 sides to a coin. There are 2 numbers on the spinner greater than three (6,9) which is 2/3.

1/2 times 2/3=0.33. The probability of getting heads and getting a number that is greater than is 0.333 or 1/3.

2

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct