A box contains 5 blue, 4 red, and 3 yellow marbles. Two marbles are randomly drawn and not replaced. What is the probability of drawing a blue then a red marble? 5/36
20/130
1/66
5/33

the answer is 5/33

Step-by-step explanation:

Total marbles = 5 blue + 4 red + 3 yellow = 12

Two marbles are selected, first is blue which gives us :

5/12 --eq 1

Then red marble is selected ( note: one marble is already drawn and not replaced so we have a total of 11 marbles )

The probability of red gave us :

4/11 --eq 2

Now we multiply eq 1 and 2

5/12 x 4/11 = 5/33

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,

step-by-step explanation: