Find all Values of b that will make the polynomial a perfect square trinomial. 289r^2 - 102r + c
Please write out how to do this so I can see the steps of what I am doing wrong. thank you!

10,404/334,084

Step-by-step explanation:

Given the polynomial

289r^2 - 102r + c

We are to find the value of c that will make it a perfect square

Divide through by 289

289r²/289 - 102r/289 + c/289

Half of the coefficient of r is 1/2(102/289)

Half of the coefficient of r = 102/578

Square the result

r² = (102/578)²

r² = 10,404/334,084

Hence the required constant is 10,404/334,084

horizontal translation of 2 units in the positive x direction

followed by

vertical translation of 3 units in the positive y direction

the two may have that, even a breakdown is probably offered