Rotate triangle P 90° clockwise about the point (2, -1). Please screenshot this and send me the answers cuz I really need help :(​

(2,0), (2,1), and (6,1)

Step-by-step explanation: I just used the desmos graphing calculator to find the answer to your problem. I don't know any formulas to solve it so I just rotated the points by hand. I also made sure they were still equidistant from the point (2,-1) because if their distances from other points changed during the rotation, then the triangle would not be equal to the first triangle and the image would've been distorted.

I hope this helps! Have a nice day.

step-by-step explanation: yes

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq