A board game has 26 tiles labeled with alphabet letters. Players draw 1 tile at a time. Over 260 different drawings, how many times are players likely to draw either a vowel or the letter Y? Show your work.

The probablty is is 41221/26 or 0.00669%

Step-by-step explanation:

Drawing tiles from the bag at one time is mathematically equivalent to drawing one tile 4 times inculding the vowel, without replacement.

If we get one of these 4 letters on draw 1, then on draw 2, we'll have 3 possible successful draws out of the 25 tiles left.

This pattern continues down to draw 4. Since each draw is independent, we just multiply the probabilities together:

constants mean the stopped points or the points on a graph that nothing is changing, hope this

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)