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Step-by-step explanation:

we have two lines you have to draw.

one is all in the bottom left quadrant (for x<=0) and one in the upper right quadrant (for x>5).

the easiest is for x>5. the line function is only

f(x) = y = 3

so, this is a horizontal line on the grid line for y = 3. it starts above x=5 and then goes all the way to the right ("to infinity and beyond !"). just, if possible, mark the starting point at x=5 as a little empty "circle" instead of a full dot, as x=5 is explicitly excluded (due to x>5).

and for x<=0 the line

f(x) = y = 4x - 3

goes sharp down but goes a little bit to the left the further down it goes. it starts with x=0, which gives y=-3 per the function.

so, the starting point (with a full dot, as x=0 is included) is (0,-3).

from there it goes sharp down and a little bit to the left.

for example the next point is for x=-1, which gives y=-7, so it is the point (-1,-7). x=-2 gives y=-11 and the point (-2,-11).

the line has to go through so these points and further down (again, "to infinity and beyond !"), as to move further left on the negative x-axis.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

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step-by-step explanation:

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