A The equation of the line that has a gradient of -4 and passes through the point (-3,-4) is:(#with solution)​

y = -4x - 16 or y +4x + 16 = 0

Step-by-step explanation:

Gradient (m) = -4

Equation of a line given gradient and one point=

y - y = m(x - x) where (x , y ) are the coordinates of the point.

Substituting...

y -(-4) = -4(x -(-3))

y + 4 = -4(x + 3)

y + 4 = -4x - 12

y = -4x - 12 - 4

y = -4x - 16 or y +4x + 16 = 0

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .