Find the mean, median, and mode of the set of data. 10, 11, 4, 7, 12, 11, 16, 6, 9, 15

Step-by-step explanation:

Mean (Average):

10.1

Median (Middle):

(10+11)/2 = 10.5

Mode (Most Common):

11

Range & TotalsResults

Range (Biggest - Smallest):

12

Total Numbers in Set:

10

Ascending Order:

4,6,7,9,10,11,11,12,15,16

Decending Order:

16,15,12,11,11,10,9,7,6,4

Even Numbers:

4,6,10,12,16

Odd Numbers:

7,9,11,11,15

Mean = 10.1

Median = 10.5

Mode = 11

Step-by-step explanation:

We are given a set of data: 10,11,4,7,12,11,16,6,9,15

First we arrange into ascending order.

4, 6, 7, 9, 10, 11, 11, 12, 15, 16

Thus, The mean of given data is 10.1

Number of data is even.

Possible median:  where, n=10

of the arranged data would be median.

Median: 10 and 11

Average of median  

Thus, The median of given data is 10.5

Mode: It is maximum repeated number of data set.

In the given data set, 11 repeated two times.

Thus, The mode the given data is 11

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x+y = 29, 5x + 2y = 100

step-by-step explanation:

i'm guessing it was a multiple first option was the correct answer

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.