Evaluate each expression given that a =-5, b=2 and c=1 b) b-a+c

c) 2b+6c

d)abc

e) -2ab/c

Given

a=-5

b=2

c=1

i) b - a + c

= 2 -(-5) + 1

=2 + 5 + 1

=8.

ii)2b + 6c

= 2(2) + 6(1)

=4 + 6

=10.

iii) abc = (-5)(2)(1)

= -10.

iv) -2ab/c

= -2(-5)(2)/1

= 20.

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

good luck on your studies! : )

david edward.