Can someone help me thx

118

Explanation:

Since ∠A=∠ADB: ∠ADB=61°. The sum of the interior angles of any triangle is 180°, thus:

61°+61°= 122
180-122=58°
∠DBA=58°

Since triangle BCD is an equilateral triangle, all the interior angles are the same:

180/3=60
∠DBC=60°
∠BCD=60°
∠CDB=60°

Since angles DBC and DBA make up angle ABC, just simply add the two angles together:

58+60=118°

Therefore, ∠ABC is 118°.