Please answer this question.​

Solution given:

CD=18m

In ∆ ACD

Tan 35=opposite/adjacent

Tan 35=CD/AC

AC=18/Tan35

AC=25.7m

again

In ∆ BCD

Tan 60=opposite/adjacent

Tan 60=CD/BC

BC=18/tan60

BC=10.4

we have

AC=AB+BC

AB=25.7-10.4

AB=15.3

Distance between A and B point is 15.3 metre

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240