PLEASE HELP M Jeb and Lori went to a florist to buy flowers. Jeb bought 6 roses and 3 carnations for $20.25. Lori bought 8 roses and 3 carnations for $25.75. Find the price of one rose and the price of one carnation.

first create an equation for Jeb flower then for Lori

then solve them by simultaneous linear equations

One rose = $2.75

One carnations = $1.25

Step-by-step explanation:

Lets make the rose = x

and carnations = y

Jeb >> 6x + 3y = 20.25

Lori >> 8x + 3y = 25.75

Solve simultaneously using elimination method.

8x + 3y = 25.75

- 6x + 3y = 20.25

2x =5.5

2x/2 = 5.5/2

x = 2.75

plug 2.75(x) into any of the two equations to find y.

6(2.75) + 3y = 20.25

16.5 + 3y = 20.25

3y = 20.25 - 16.5

3y = 3.75

3y/3 = 3.75/3

y = 1.25

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

to find the total number of combinations, multiply the quantity of each item by each other:

2 pairs of shoes x 3 pairs of shorts = 6 different combinations.