At a pet store, Rhonda paid $55 for 8 dog bowls and 6 bones. Kelly paid $32.50 for 2 dog bowls and 9 bones. Determine the cost of one dog bowl (x) and one bone (y). Write a system of linear equations that models this situation.

8d + 6b = 55

2d + 9b = 32.50

Step-by-step explanation:

let 'd' = # dog bowls

let 'b' + # bones

Rhonda:  8d + 6b = 55

Kelly:  2d + 9b = 32.50

we can multiply Kelly's equation by -4 to eliminate the 'd' terms:

Kelly: -4(2d + 9b) = 32.5(-4)

-8d - 36b = -130

now add the above equation to Rhonda's equation:

  -8d - 36b = -130

+  8d + 6b = 55

-30b = -75

b = 2.50

now we can use either equation and substitute 2.5 for 'b' to find 'd'

2d + 9(2.5) = 32.5

2d + 22.5 = 32.5

2d = 10

d = 5

a) 15/7

step-by-step explanation:

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above