Find the 23rd term of the arithmetic sequence whose common difference is d=4 and whose first term is a^1 = 3.

the 23rd term of the arithmetic sequence=91

Step-by-step explanation:

The nth term of an arithmetic sequence is given as

an=a+  (n-1) d

Given common difference , d=4 and

first term is a^1 = 3.

We have that

a₂₃=3+  (23-1) 4

a₂₃=3+  (22) 4

a₂₃=3+  88

a₂₃=91

the 23rd term of the arithmetic sequence=91

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this

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step-by-step explanation: