In November, the rain in a certain valley tends to fall in storms of several days duration. The unconditional probability of rain on any day of the month is 0.600. But the probability of rain on a day that follows a rainy day is 0.900, and the probability of rain on a day following a nonrainy day is 0.300. Find the probability of rain on November 1 and 2. but not on November 3. Find the probability of rain on November 1 and 2, but not on November 3.​

0.0594 = 5.94% probability of rain on November 1 and 2, but not on November 3.​

Step-by-step explanation:

Rain on November 1:

0.9 of 0.6(rain on Oct 31).

0.3 of 0.4(not rain on Oct 31).

Rain on November 2:

Considering rain on November 1, 0.9 probability of rain.

Rain on November 3:

Considering rain on November 2, 0.1 probability of rain.

Find the probability of rain on November 1 and 2, but not on November 3.​

Multiplicating the probabilities:

0.0594 = 5.94% probability of rain on November 1 and 2, but not on November 3.​

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.