Volume of square based pyramid is 1568 cm3 and half of the length of the side of the base is 7cm. Calculate the area of triangular faces of pyramid.
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1393.84

Step-by-step explanation:

since the formula for a square base pyramid is a^2×h/3

we can find out the height for the pyramid by dividing the a^2×h/3 by a^2 =h/3

1568/7^2=32 since 32 = h/3 we multiply by 3 to find the height which = 96

now that we have the height we usee the pathagorean Therom to find the height of one of the face triangles

so 96^2+3.5^2=L^2 so L =96.06

so now that we have all we need

the surface area of the square at the bottom of the pyramid is 7×7

the surface area of the triangles are 96.06 ×7/2 since the area of a triangle is h×b/2

since there are 4 triangles and on square 49+4(96.06×7/2)= 1393.84

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}