1. Find the numbers a, b, c such that 2x4 + 2x3 +5x2 + 3x + 3 = (x2 + x +1)(ax2+bx+c)
for all values of x.​

a = 2

b = 0

c = 3

Step-by-step explanation:

if I understand correctly the problem should look like

2x⁴ + 2x³ + 5x² + 3x + 3 = (x² + x + 1)(ax² + bx + c)

let's calculate the right side

ax⁴ + ax³ + ax² + bx³ + bx² + bx + cx² + cx + c

as there is only one term of x⁴, we know a = 2

as there is only one term without any x, we know c = 3

now we get

2x⁴ + 2x³ + 2x² + bx³ + bx² + bx + 3x² + 3x + 3

remember, that is equal to

2x⁴ + 2x³ + 5x² + 3x + 3

after subtracting 2x⁴ and 3 from both sides we get

2x³ + 5x² + 3x = 2x³ + 2x² + bx³ + bx² + bx + 3x² + 3x

we subtract 2x³ and 3x from both sides and get

5x² = 2x² + bx³ + bx² + bx + 3x² = 5x² + bx³ + bx² + bx

we subtract 5x² from both sides and get

0 = bx³ + bx² + bx

=> b must be 0 to make this true for all values of x

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.